MinerU/mineru/utils/boxbase.py

import math


def is_in(box1, box2) -> bool:
    """box1是否完全在box2里面."""
    x0_1, y0_1, x1_1, y1_1 = box1
    x0_2, y0_2, x1_2, y1_2 = box2

    return (
        x0_1 >= x0_2  # box1的左边界不在box2的左边外
        and y0_1 >= y0_2  # box1的上边界不在box2的上边外
        and x1_1 <= x1_2  # box1的右边界不在box2的右边外
        and y1_1 <= y1_2
    )  # box1的下边界不在box2的下边外


def bbox_relative_pos(bbox1, bbox2):
    """判断两个矩形框的相对位置关系.

    Args:
        bbox1: 一个四元组，表示第一个矩形框的左上角和右下角的坐标，格式为(x1, y1, x1b, y1b)
        bbox2: 一个四元组，表示第二个矩形框的左上角和右下角的坐标，格式为(x2, y2, x2b, y2b)

    Returns:
        一个四元组，表示矩形框1相对于矩形框2的位置关系，格式为(left, right, bottom, top)
        其中，left表示矩形框1是否在矩形框2的左侧，right表示矩形框1是否在矩形框2的右侧，
        bottom表示矩形框1是否在矩形框2的下方，top表示矩形框1是否在矩形框2的上方
    """
    x1, y1, x1b, y1b = bbox1
    x2, y2, x2b, y2b = bbox2

    left = x2b < x1
    right = x1b < x2
    bottom = y2b < y1
    top = y1b < y2
    return left, right, bottom, top


def bbox_distance(bbox1, bbox2):
    """计算两个矩形框的距离。

    Args:
        bbox1 (tuple): 第一个矩形框的坐标，格式为 (x1, y1, x2, y2)，其中 (x1, y1) 为左上角坐标，(x2, y2) 为右下角坐标。
        bbox2 (tuple): 第二个矩形框的坐标，格式为 (x1, y1, x2, y2)，其中 (x1, y1) 为左上角坐标，(x2, y2) 为右下角坐标。

    Returns:
        float: 矩形框之间的距离。
    """

    def dist(point1, point2):
        return math.sqrt((point1[0] - point2[0]) ** 2 + (point1[1] - point2[1]) ** 2)

    x1, y1, x1b, y1b = bbox1
    x2, y2, x2b, y2b = bbox2

    left, right, bottom, top = bbox_relative_pos(bbox1, bbox2)

    if top and left:
        return dist((x1, y1b), (x2b, y2))
    elif left and bottom:
        return dist((x1, y1), (x2b, y2b))
    elif bottom and right:
        return dist((x1b, y1), (x2, y2b))
    elif right and top:
        return dist((x1b, y1b), (x2, y2))
    elif left:
        return x1 - x2b
    elif right:
        return x2 - x1b
    elif bottom:
        return y1 - y2b
    elif top:
        return y2 - y1b
    return 0.0


def get_minbox_if_overlap_by_ratio(bbox1, bbox2, ratio):
    """通过calculate_overlap_area_2_minbox_area_ratio计算两个bbox重叠的面积占最小面积的box的比例
    如果比例大于ratio，则返回小的那个bbox, 否则返回None."""
    x1_min, y1_min, x1_max, y1_max = bbox1
    x2_min, y2_min, x2_max, y2_max = bbox2
    area1 = (x1_max - x1_min) * (y1_max - y1_min)
    area2 = (x2_max - x2_min) * (y2_max - y2_min)
    overlap_ratio = calculate_overlap_area_2_minbox_area_ratio(bbox1, bbox2)
    if overlap_ratio > ratio:
        if area1 <= area2:
            return bbox1
        else:
            return bbox2
    else:
        return None


def calculate_overlap_area_2_minbox_area_ratio(bbox1, bbox2):
    """计算box1和box2的重叠面积占最小面积的box的比例."""
    # Determine the coordinates of the intersection rectangle
    x_left = max(bbox1[0], bbox2[0])
    y_top = max(bbox1[1], bbox2[1])
    x_right = min(bbox1[2], bbox2[2])
    y_bottom = min(bbox1[3], bbox2[3])

    if x_right < x_left or y_bottom < y_top:
        return 0.0

    # The area of overlap area
    intersection_area = (x_right - x_left) * (y_bottom - y_top)
    min_box_area = min([(bbox1[2] - bbox1[0]) * (bbox1[3] - bbox1[1]),
                        (bbox2[3] - bbox2[1]) * (bbox2[2] - bbox2[0])])
    if min_box_area == 0:
        return 0
    else:
        return intersection_area / min_box_area


def calculate_iou(bbox1, bbox2):
    """计算两个边界框的交并比(IOU)。

    Args:
        bbox1 (list[float]): 第一个边界框的坐标，格式为 [x1, y1, x2, y2]，其中 (x1, y1) 为左上角坐标，(x2, y2) 为右下角坐标。
        bbox2 (list[float]): 第二个边界框的坐标，格式与 `bbox1` 相同。

    Returns:
        float: 两个边界框的交并比(IOU)，取值范围为 [0, 1]。
    """
    # Determine the coordinates of the intersection rectangle
    x_left = max(bbox1[0], bbox2[0])
    y_top = max(bbox1[1], bbox2[1])
    x_right = min(bbox1[2], bbox2[2])
    y_bottom = min(bbox1[3], bbox2[3])

    if x_right < x_left or y_bottom < y_top:
        return 0.0

    # The area of overlap area
    intersection_area = (x_right - x_left) * (y_bottom - y_top)

    # The area of both rectangles
    bbox1_area = (bbox1[2] - bbox1[0]) * (bbox1[3] - bbox1[1])
    bbox2_area = (bbox2[2] - bbox2[0]) * (bbox2[3] - bbox2[1])

    if any([bbox1_area == 0, bbox2_area == 0]):
        return 0

    # Compute the intersection over union by taking the intersection area
    # and dividing it by the sum of both areas minus the intersection area
    iou = intersection_area / float(bbox1_area + bbox2_area - intersection_area)

    return iou


def _is_in(box1, box2) -> bool:
    """box1是否完全在box2里面."""
    x0_1, y0_1, x1_1, y1_1 = box1
    x0_2, y0_2, x1_2, y1_2 = box2

    return (x0_1 >= x0_2 and  # box1的左边界不在box2的左边外
            y0_1 >= y0_2 and  # box1的上边界不在box2的上边外
            x1_1 <= x1_2 and  # box1的右边界不在box2的右边外
            y1_1 <= y1_2)  # box1的下边界不在box2的下边外